rajiv: how to solve 2.5=(1.06)^h
2.5=(1.06)^h
formula: b^h = a equals h = log
b(a) (for a, b>0 and b <>0)
2.5=(1.06)^h
h = log( 2.5, 1.06 )
[input]log( 2.5, 1.06 )[/input]
test:
[input]1.06^15.72520854388776499211876987921071708374706931652257517168334[/input]
