log9(x+8)+log3(x+6)=2 I keep ending up with log3^(x+8)/log3^9 +log3(x+6)=2 then log9(x+8)(x+6)=2log3 (x+8)(x+6)=1 My answer is either suppose to be -4 or-7, -8 or -6,or 13 or -3 but no matter what I do I can't seem to get it.
+129839 log9(x+8)+log3(x+6) = 2
Uisng the change of base formula, we have
log ( x + 8) / log 9 + log (x + 6) / log 3 = 2 multiply both sides by log 9 * log 3
log 3 *log ( x + 8) +log 9* log ( x + 6) = 2 * log9 * log3 by the exponent law, we can write
log (x + 8)^log3 + log(x + 6)^log9 = 2*log9 * log 3 and further, we can write
log[ (x + 8)^log3 * (x + 6)^log9] = 2*log9 * log 3 this would be difficult to solve by normal means
WolframAlpha gives the solution as ≈ -2.24754
