Use the fact that a^2 - b^2 = (a+b)(a-b) so we have: (2001+1992)*9/[(2003+1997)*6]
or 3993*9/(4000*6) ≈ 1.497
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Good thinking Alan :)
Here is another way - I used the calculator. LOL
(2001^2 - 1992^2) / (2003^2 - 1997^2) = 1.497375
actually sorry guys my bad... it should have been " (2001^2 - 1999^2) / (2003^2 - 1997^2) = ? "
i coulnt notice the "a^2 - b^2" fact, thanks for the answer Alan and who tried to help me :)
with the a^2 - b^2 fact i easily found the answer of my question it is 1/3 :)
and im really sory for my mistake, thank you all for helping out :)