ifrogot1: 2^x+2^y=10
x+y=4
How do I solve this system of equations?
x+y=4 --> y=4-x
2
x + 2
y = 10 sub in 4-x for y
2
x + 2
4-x = 10
2
x + 2
4/2
x = 10
Multiply both sides by 2
x 2
x2
x + 2
4 = 10*2
x (2
x)
2 - 10*2
x + 16 = 0
Let g=2
x g
2 - 10g + 16 = 0
So i need 2 numbers that multply to +16 and add to -10
They are -8 and -2 so
(g-8)(g-2)=0
g=8 or g=2
8=2
x or 2=2
x 2
3=2
x or 2
1=2
x x=3 or x=1
now y=4-x
so
x=3, y=1 OR x=1. y=3
solutions are (3,1) or (1,3)
check
http://www.wolframalpha.com/input/?i=2%5Ex%2B2%5Ey%3D10%2C+x%2By%3D4