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(16x^2y^-4z^-1)^0/ y^2 what does zero mean? 

 Apr 26, 2016
 #1
avatar+37184 
+5

ANYTHING (except '0')    raised to the 0 power is = 1    so the WHOLE NUMERATOR = 1

=

1/y^2

 Apr 26, 2016

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