What is the value of b if 5^b + 5^b + 5^b + 5^b + 5^b = 25^(b - 1).

I noticed I see five '5^b's. Thus, the equation would be:

\(5^{b+1}=25^{b-1}\)

25 = 5^2, so the equation would be:

\(5^{b+1}=5^{2b-2}\)

Since they are equal and they have the same base, then:

b + 1 = 2b - 2.

Solving for b, we get \(b=3\).