What is the value of b if 5^b + 5^b + 5^b + 5^b + 5^b = 25^(b - 1).
I noticed I see five '5^b's. Thus, the equation would be:
\(5^{b+1}=25^{b-1}\)
25 = 5^2, so the equation would be:
\(5^{b+1}=5^{2b-2}\)
Since they are equal and they have the same base, then:
b + 1 = 2b - 2.
Solving for b, we get \(b=3\).
