+0

# Exponents

0
100
1

Solve for y if 9^y = 3^6

\(\phantom{27 27^4 81 81^2 81^3 81^4}\)

\(\phantom{1^2 + 2^2 + \dots + n^2}\)

Jul 1, 2022

#1
+2448
0

Simplify the left-hand side: \({3^2}^y = 3^{2y}\)

Note that the exponents have the same bases, so we have \(2y = 6\)

Now, just solve for y.

Jul 1, 2022

#1
+2448
0

Simplify the left-hand side: \({3^2}^y = 3^{2y}\)

Note that the exponents have the same bases, so we have \(2y = 6\)

Now, just solve for y.

BuilderBoi Jul 1, 2022