what is the value of n such that, 81^n=9*27*27*9?
81^n=9*27*27*9?
n ==Log[9*27*27*9) / log(81)
n==2.5
Alternatively:
81n=92n
9∗27∗27∗9=9∗3∗9∗3∗9∗9=95
Hence 92n=95 so 2n=5 or n=5/2