what is the value of n such that, 81^n=9*27*27*9?
81^n=9*27*27*9?
n ==Log[9*27*27*9) / log(81)
n==2.5
Alternatively:
\(81^n=9^{2n}\)
\(9*27*27*9=9*3*9*3*9*9=9^5\)
Hence \(9^{2n}=9^5\) so \(2n=5\) or \(n=5/2\)
