9ln (x-3)-11 ln x
please show steps
thank you in advance!
1. a*ln(b) = ln(b^a) so 9*ln(x-3) - 11*ln(x) can be written as ln(x-3)^9 - ln(x^11)
2. ln(c) - ln(d) = ln(c/d) so ln(x-3)^9 - ln(x^11) can be written as ln( (x-3)^9/x^11 ) i.e. ln( ( x-3)9x-11 )
(Edited to correct mistaken sign)
. ln(c) - ln(d) = ln(c/d)
so ln(x-3)^9 - ln(x^11) can be written as ln( (x-3)^9 / x^11 ) i.e. ln( ( x-3)9 / x11 )
