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Express\(\sqrt{x}\) ÷\(\sqrt{y}\) as a common fraction, given:

\(((1/2)^2+(1/3)^2)/(1/4)^2+(1/5)^2\)=\(13x/41y\) 

 

It's due in 10 minutes so could you please hurry!!!!! Thank you so much! Also can you explain what you do so I can learn from it. Thanks again!!! :)

 Nov 24, 2020
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(1/2)2+(1/3)2=13x solve for x

(1/4)2+(1/5)2=41y solve for y

 

1/4+1/9=13x

1/16+1/25=41y

 

13/36=13x

41/400=41y

 

1/36=x

1/400=y

 

√(1/36) / √(1/400) = (1/6) / (1/20)

 

20/6 or 10/3

 Nov 25, 2020

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