expressions

c(c − d) + cd − d3     so we have

-3[-3 - (-2)] + (-3)(-2) - (-2)3  = 

-3 [ -3 + 2 ] + 6  + 6    =

-3 [ -1]  + 12

3  + 12  = 

15

Hi 

Thanks for that,  but the d3, should have been to the power of 3, which to me on that part would be -8?

so using your formula below

its 

-3[-3 - (-2)] + (-3)(-2) - (-8) =

-3 [-1] + 6 + 8 = 

-3 [-1] + 14 =

3 + 14 

= 17

thanks,  17 was correct with the correction!