A side of the triangle below has been extended to form an exterior angle. What is the value of x.
Let us denote the interior angle(not 114, not x) as y. Because the exterior angle plus the interior angle sum to $180^\circ$, we have $164+y=180$, which gives $y=16^\circ$. Now, we use the formula for the sum of the angles of a triangle. It states that the sum of all the angles in a triangle is equal to $180^\circ$, so we have $16+114+x=180$, which gives $x=180-16-114$, which gives $\boxed{x=50}$
Let us denote the interior angle(not 114, not x) as y. Because the exterior angle plus the interior angle sum to $180^\circ$, we have $164+y=180$, which gives $y=16^\circ$. Now, we use the formula for the sum of the angles of a triangle. It states that the sum of all the angles in a triangle is equal to $180^\circ$, so we have $16+114+x=180$, which gives $x=180-16-114$, which gives $\boxed{x=50}$