$f^{-1}$ of $f(x)=\frac{7-8x}{3}$

Question: \(f^{-1} \text{ of }f(x)=\frac{7-8x}{3}\)

\(\text{Or }y = \frac{7-8x}{3}\)

\(3y=7-8x\)

\(3y-7=-8x\)

\(x=\dfrac{7-3y}{8}\)

\(f^{-1}(y)=\dfrac{7-3y}{8}\)
\(f^{-1}(x)=\dfrac{7-3x}{8}\)

Finish!!