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F=9/5(K-273.15)+32 solve for k

 May 28, 2014

Best Answer 

 #1
avatar+1006 
+6

$${\mathtt{F}} = {\frac{{\mathtt{9}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{K}}{\mathtt{\,-\,}}{\mathtt{273.15}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{32}}$$

$${\mathtt{F}}{\mathtt{\,-\,}}{\mathtt{32}} = {\frac{{\mathtt{9}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{K}}{\mathtt{\,-\,}}{\mathtt{273.15}}\right)$$

$${\frac{{\mathtt{5}}}{{\mathtt{9}}}}{\mathtt{\,\times\,}}\left({\mathtt{F}}{\mathtt{\,-\,}}{\mathtt{32}}\right) = {\mathtt{K}}{\mathtt{\,-\,}}{\mathtt{273.15}}$$

$${\frac{{\mathtt{5}}}{{\mathtt{9}}}}{\mathtt{\,\times\,}}\left({\mathtt{F}}{\mathtt{\,-\,}}{\mathtt{32}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{273.15}} = {\mathtt{K}}$$

 

I isolated 'K', is there any more?

 May 28, 2014
 #1
avatar+1006 
+6
Best Answer

$${\mathtt{F}} = {\frac{{\mathtt{9}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{K}}{\mathtt{\,-\,}}{\mathtt{273.15}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{32}}$$

$${\mathtt{F}}{\mathtt{\,-\,}}{\mathtt{32}} = {\frac{{\mathtt{9}}}{{\mathtt{5}}}}{\mathtt{\,\times\,}}\left({\mathtt{K}}{\mathtt{\,-\,}}{\mathtt{273.15}}\right)$$

$${\frac{{\mathtt{5}}}{{\mathtt{9}}}}{\mathtt{\,\times\,}}\left({\mathtt{F}}{\mathtt{\,-\,}}{\mathtt{32}}\right) = {\mathtt{K}}{\mathtt{\,-\,}}{\mathtt{273.15}}$$

$${\frac{{\mathtt{5}}}{{\mathtt{9}}}}{\mathtt{\,\times\,}}\left({\mathtt{F}}{\mathtt{\,-\,}}{\mathtt{32}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{273.15}} = {\mathtt{K}}$$

 

I isolated 'K', is there any more?

GoldenLeaf May 28, 2014
 #2
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0

no thats it thank you :)

 May 28, 2014
 #3
avatar+1006 
0

No problem Anon!

 May 28, 2014

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