+0  
 
0
42
1
avatar

f'(x)= 1/3x3+ 4x ???

 

how do i solve this?

Guest Jul 7, 2017
Sort: 

1+0 Answers

 #1
avatar+89628 
0

f'(x)= 1/3x3+ 4x 

f'(x)= (1/3)x^3+ 4x 

Is this what you mean?   The symbol for 'to the power of' is ^

 

\(f'(x)= \frac{1}{3}x^3+ 4x \\ f(x)=\int\;\frac{1}{3}x^3+ 4x\;dx \\ f(x)=\frac{1}{3*4}x^4+ \frac{4x^2}{2}+c\\ f(x)=\frac{x^4}{12}+ 2x^2+c\\\)

Melody  Jul 7, 2017

9 Online Users

avatar
avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details