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f ''(x) = −2 + 18x − 12x^2,    f(0) = 8,    f '(0) = 14

 

find f(x)=

 Nov 12, 2016
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f ''(x) = −2 + 18x − 12x^2,    f(0) = 8,    f '(0) = 14

 

find f(x)=

 

\(f ''(x) = −2 + 18x − 12x^2\\ f'(x)=-2x+9x^2-4x^3+k\\ f'(0)=14\qquad so\qquad k=14\\ f'(x)=-2x+9x^2-4x^3+14\\ f(x)=-x^2+3x^3-x^4+14x+c\\ f(0)=8 \qquad so\qquad c=8\\ f(x)=-x^2+3x^3-x^4+14x+8\\ \)

 Nov 12, 2016

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