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find the vertex of the graph of f(x)=3x^2+6x-10

 Apr 12, 2016
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f(x)=3x^2+6x-10

 

The x coordinate of the vertex is given by    -b/ [2a]   where b = 6 and a  = 3......so we have...

 

-6/ [2(3)]  =    -1

 

And we can put this value into the function to find the y coordinate of the vertex....so....

 

f(-1)  = 3(-1)^2 + 6(-1) - 10  =  3 - 6 - 10  =   -13

 

So the vertex is  (-1, -13)

 

 

 

cool cool cool

 Apr 12, 2016

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