f(x)=(8x^3+3)^5,f'(x)=?

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Guest Jan 13, 2015

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Best Answer

$$\\f(x)=(8x^3+3)^5\\\\\\
f'(x)=5(8x^3+3)^4\times (24x^2)\\\\
f'(x)=120x^2(8x^3+3)^4\\\\$$

Melody Jan 13, 2015

Melody · Answer 1 · 2015-01-13T08:08:33

$$\\f(x)=(8x^3+3)^5\\\\\\
f'(x)=5(8x^3+3)^4\times (24x^2)\\\\
f'(x)=120x^2(8x^3+3)^4\\\\$$

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