f(x)<=x^2-x<=f(x+1)-x
prove that f(x)=x^2-x,for every any x as a real number
am i supposed to state x+1=ω???
please help
I found it
If f(x) = x^2 - x then f(x+1)- x = x^2 which means that if x is less than zero f(x) is greater than f(x+1)-x, so your proposition can't be true for all real x.
