f(x)=x^2-px-6, and f(-2)=6 find the value p.

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Guest Jan 13, 2017

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f(x)=x^2-px-6, and f(-2)=6 find the value p.

\(f(x)=x^2-px-6\\ f(-2)=(-2)^2-p*(-2)-6\\ (-2)^2-p*(-2)-6=6\\ 4+2p-6=6\\ 2p-2=6\\ 2p=8\\ p=4\)

Melody Jan 13, 2017

Melody · Answer 1 · 2017-01-13T01:09:30

f(x)=x^2-px-6, and f(-2)=6 find the value p.

\(f(x)=x^2-px-6\\ f(-2)=(-2)^2-p*(-2)-6\\ (-2)^2-p*(-2)-6=6\\ 4+2p-6=6\\ 2p-2=6\\ 2p=8\\ p=4\)