Factor the following:
2 x^2 + 7 x + 3
Factor the quadratic 2 x^2 + 7 x + 3. The coefficient of x^2 is 2 and the constant term is 3. The product of 2 and 3 is 6. The factors of 6 which sum to 7 are 1 and 6. So 2 x^2 + 7 x + 3 = 2 x^2 + 6 x + x + 3 = 3 (2 x + 1) + x (2 x + 1):
3 (2 x + 1) + x (2 x + 1)
Factor 2 x + 1 from 3 (2 x + 1) + x (2 x + 1):
Answer: | (2x + 1) (x + 3)
Factor the following:
2 x^2 + 7 x + 3
Factor the quadratic 2 x^2 + 7 x + 3. The coefficient of x^2 is 2 and the constant term is 3. The product of 2 and 3 is 6. The factors of 6 which sum to 7 are 1 and 6. So 2 x^2 + 7 x + 3 = 2 x^2 + 6 x + x + 3 = 3 (2 x + 1) + x (2 x + 1):
3 (2 x + 1) + x (2 x + 1)
Factor 2 x + 1 from 3 (2 x + 1) + x (2 x + 1):
Answer: | (2x + 1) (x + 3)
