factor by grouping

Question

+2

900

1

+80

x^3+8x^2+6x+48

gadzooks1753 Nov 28, 2017

TheXSquaredFactor · Answer 1 · 2017-11-28T01:02:45

$(x^3+8x^2)+(6x+48)$	Factor out the individual GCF of the terms inside of the parentheses.
$x^2(x+8)+6(x+8)$	(x+8) is common in both, so we can rewrite.
$(x^2+6)(x+8)$	Nothing more can be done here.