+118658 a^2-1/3a+4 = 10
I will assume that you want me to solve ( a^2-1)/(3a+4) = 10
\(\frac{( a^2-1)}{(3a+4)} = 10\\ \frac{( a^2-1)}{(3a+4)} \times \frac{3a+4}{1}= 10\times \frac{3a+4}{1}\\ a^2-1= 30a+40\\ a^2-30a-41= 0\\ \triangle=900+164=1064=4*266\\ a=\frac{30\pm\sqrt{4*266}}{2}\\ a=15\pm\sqrt{266}\\ \)
OR maybe you really have stated correctly what you wanted...
\(a^2-\frac{1}{3}a+4=10\\ a^2-\frac{1}{3}a-6=0\\ 3a^2-a-18=0\\ \triangle=1+216=217\\ a=\frac{1\pm\sqrt{217}}{6}\)
