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Factor the expression completely over the complex numbers.

 

SamJones  Jan 26, 2018
 #1
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+1

Solve for y:

y^3 + 2 y^2 + 16 y + 32 = 0

 

The left hand side factors into a product with two terms:

(y + 2) (y^2 + 16) = 0

 

Split into two equations:

y + 2 = 0 or y^2 + 16 = 0

 

Subtract 2 from both sides:

y = -2 or y^2 + 16 = 0

 

Subtract 16 from both sides:

y = -2 or y^2 = -16

 

Take the square root of both sides:

y = -2    or    y = 4i    or    y = -4i

Guest Jan 26, 2018

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