factor (x^3)+(1/512)

Question

0

786

1

Guest Feb 5, 2015

+118609

+5

Best Answer

$$\\\boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}\\\\
x^3+\left(\frac{1}{8}\right)^3
=\left(x+\frac{1}{8}\right)\left(x^2-\frac{x}{8}+\frac{1}{64}\right)$$

Melody Feb 5, 2015

Melody · Answer 1 · 2015-02-05T11:19:42

$$\\\boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}\\\\
x^3+\left(\frac{1}{8}\right)^3
=\left(x+\frac{1}{8}\right)\left(x^2-\frac{x}{8}+\frac{1}{64}\right)$$

.