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Find the sum of the distinct prime factors of 123 + 456 + 789.

 Jun 14, 2024
 #1
avatar+1075 
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Let's first factor each number to the smallest it can be. We get

\(3 \cdot 41 + 3 \cdot 2^3 \cdot 19+ 3 \cdot 263\)

 

Notice that every number is a factor of 3. We get

\(3(41+152+263)\)

 

Adding every number inside the parenthesis, we get

\(3(456)\\ 3^2 \cdot 2^3 \cdot 19 \)

 

So 3, 2, and 19 are our numbers. 

 

\(3+2+19=24\)

 

So 24 is our answer. 

 

Thanks! :)

 Jun 14, 2024

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