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Find the sum of the distinct prime factors of 333 + 183 + 401.

 Jun 14, 2024
 #1
avatar+1075 
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First, let's add all three numbers up. We get

\(333+183+401=917\)

 

Now, we must find factors of 917. 

 

There's actually only 4 of them, two of them which are 917 and 1. 

The other two are 7 and 131. 

 

\(7*131=917\)

 

So our two prime factors are 7 and 131. 

 

We have \(7+131=138\)

 

So 138 is our final answer. 

 

Thanks! :)

 Jun 14, 2024

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