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Find the sum of the distinct prime factors of 248 + 113 + 2870.

 Jun 14, 2024
 #1
avatar+1926 
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First, let's add up all 3 of the numbers. 

We get \(248 + 113 + 2870 = 3231\)

 

Now, we have to factor 3231. Notice that \(3+2+3+1=9\), so 3231 is divisble by 3. 

 

We get \(3231/3=1077 \). Notice that \(1+7+7=15\), so 1077 is also divisble by 3. 

\(1077/3 = 359\)

 

359 is prime. 

 

So now, we have 2 factors, 3 and 359. 

\(3+359=362\)

 

So our final answer is 362. 

 

Thanks! :)

 Jun 14, 2024

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