+1439 Find the sum of the distinct prime factors of 5005 + 6192 + 11823.
+1926 First, let's add up all 3 of the numbers we have. We get
\(5005 + 6192 + 11823=23020\)
Now, we want to find the prime factors of 23020. We know that 23020 is divisble by 10, so 2 and 5 are factors.
\(23020/10=2302\)
2302 is divisble by 2, so we have \(2302/2=1151\)
1151 is actually prime, so we can stop here.
This means that 23020 has 3 prime factors. \(1151, 2, 5\)
Adding all of these on, we get
\(1151+2+5=1158\)
So 1158 is our answer.
Thanks! :)
