+0  
 
0
65
1
avatar

Find the value of n that satisfies 2*(n+1)!+6*n!=4*(n+1)!, where n! = n * (n-1) * (n-2)...2*1.

 Jan 29, 2021
 #1
avatar+819 
0

Hello Guest!

 

2*(n+1)!+6*n!=4*(n+1)!

6n! = 2(n+1)!

6n! = 2n! * (n+1)

3 = n + 1

2 = n

 

I hope this helped. :))

 

=^._.^=

 Jan 29, 2021

56 Online Users

avatar
avatar
avatar
avatar
avatar