factoring 32x^3y^4 - 48x^2y

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here is the problemFactor: 32x^3y^4 - 48x^2y

Guest Dec 1, 2016

CPhill · Answer 1 · 2016-12-01T07:05:14

32x^3y^4 - 48x^2y

Take out the GCF's first

GCF 32 , 48 = 16

GCF x^3 , x ^2 = x^2

GCF y^4 , y = y so we have

16x^2y [ 2xy^3 - 3]