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x^6+2x^3+1 fully factored?

 Sep 23, 2017
 #1
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x6 + 2x3 + 1

Since this is a perfect square, it can be factored as:

(x3 + 1)(x3 + 1)

 

Each of these factors is a perfect cube, so it can be factored as:

(x + 1)(x2 - x + 1)(x + 1)(x2 - x + 1)

 

This can be rewritten as:  (x + 1)2((x2 - x + 1)2

 Sep 23, 2017

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