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x^6+2x^3+1 fully factored?
x6 + 2x3 + 1
Since this is a perfect square, it can be factored as:
(x3 + 1)(x3 + 1)
Each of these factors is a perfect cube, so it can be factored as:
(x + 1)(x2 - x + 1)(x + 1)(x2 - x + 1)
This can be rewritten as: (x + 1)2((x2 - x + 1)2