x^3 - 7x + 6x = 0 simplify
x^3 - x = 0 factor
x ( x^2 - 1) =
x(x + 1) (x - 1) = 0
Setting each factor to 0 and solving for x produces
x = 0 x = -1 and x = 1
Maybe that was meant to be
x^3 -7x^2+6x = 0 ? factor out 'x'
x (x^2-7x+6) =0 factor
x (x -6)(x-1)= 0
Set each factor = 0 and solve for 'x' = 0 6 1