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avatar+2442 

Please help asap, ty!

 Sep 13, 2018
 #1
avatar+99297 
+3

x^4-36 

this is the difference of two squares 

so

\(= (x^2-6)(x^2+6)\\ =(x-\sqrt 6)(x+\sqrt 6)(x^2+6)\)

 

You can only go further than this if you accept complex (imaginary) roots.

 

---

 

64c^3+1

This is the sum of 2 cubes     \((4c)^3+1^3\)

 

I expect you can look at the link below and work this one out for yourself.   :)

 

 

factoring a sum or difference of 2 cubes link

 Sep 13, 2018
 #2
avatar+2442 
+3

Got it! Thanks ^-^

(4c+1)(16c^2-4c+1)

RainbowPanda  Sep 13, 2018

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