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#1**+3 **

x^4-36

this is the difference of two squares

so

\(= (x^2-6)(x^2+6)\\ =(x-\sqrt 6)(x+\sqrt 6)(x^2+6)\)

You can only go further than this if you accept complex (imaginary) roots.

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64c^3+1

This is the sum of 2 cubes \((4c)^3+1^3\)

I expect you can look at the link below and work this one out for yourself. :)

Melody Sep 13, 2018