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# ​ Factoring polynomials (GCF)

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RainbowPanda  Sep 13, 2018
#1
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x^4-36

this is the difference of two squares

so

$$= (x^2-6)(x^2+6)\\ =(x-\sqrt 6)(x+\sqrt 6)(x^2+6)$$

You can only go further than this if you accept complex (imaginary) roots.

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64c^3+1

This is the sum of 2 cubes     $$(4c)^3+1^3$$

I expect you can look at the link below and work this one out for yourself.   :)

factoring a sum or difference of 2 cubes link

Melody  Sep 13, 2018
#2
+2077
+3

Got it! Thanks ^-^

(4c+1)(16c^2-4c+1)

RainbowPanda  Sep 13, 2018