When factoring the sum or difference of cubes how do you solve it with a decimal
\(\sqrt[3]{432}+\sqrt[3]{250m^3}\)
Both cubes equal to a decimal.. I dont know how to solve them with decimals.
Help would be much appreciated thanks
∛432 + ∛[250m^3 ] =
∛[216 *2] + ∛[125 *2 * m^3] =
∛216 * ∛2 + ∛125 * ∛2 * ∛m^3 =
6∛2 + 5∛2 * m =
∛2 * [ 6 + 5m ]
