+288 Factor
\(ab^3 - a^3 b + bc^3 - b^3 c + ca^3 - c^3 a.\)
----------------Thanks! 
+934 The way I would approach this is by factoring by grouping.
ab^3-a^3b= (ab)(b^2-a^2)
bc^3-b^3c= (bc)(c^2-b^2)
ca^3-c^3a= (ca)(a^2-c^2)
Using difference of squares...
ab^3-a^3b= (ab)(b^2-a^2)= (ab)(b+a)(b-a)
bc^3-b^3c= (bc)(c^2-b^2)= (bc)(c+b)(c-b)
ca^3-c^3a= (ca)(a^2-c^2)= (ca)(a+c)(a-c)
Putting the whole thing together, you get (ab)(b+a)(b-a)+ (bc)(c+b)(c-b)+ (ca)(a+c)(a-c) which is completely factored.
Hope it helps!
