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Can someone show the steps to factor x^3-x^2+x-1
 Sep 28, 2012
 #1
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x^3-x^2+x-1
=(x*x*x)-(x*x)+x-1
=x(x^2-x+1)-1

Not sure if this is right, but it should help.
 Sep 29, 2012
 #2
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No, but thanks anyway. That's not the answer the book gave. The book gave as the answer (x+1) (x-1)^ But we have to show how we got the answer.
 Sep 30, 2012
 #3
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The correct answer is χ^3-χ^2χ+1 => χ^2*(χ-1)+χ-1 => (χ^2+1)*(χ-1)
 Sep 30, 2012
 #4
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Nice post. I like it. Thanks for sharing these information. Keep it up.
 Nov 7, 2012

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