factoring

(9x^5+25x^3- 4) - (x^5 - 8x^3 - 4) = (9-1)x^5 + (25+8)x^3 + (-4+4) = 8x^5 + 33x^3

Hey there, Guest!

So, first, we need to distribute the negative sign:

$=9x^5+25x^3−4+−1(x^5−8x^3−4)$

$=9x^5+25x^3+−4+−1x^5+−1(−8x^3)+(−1)(−4)$

$=9x^5+25x^3+−4+−x^5+8x^3+4$

Then, we can combine like terms:

$=9x^5+25x^3+−4+−x^5+8x^3+4$

$=(9x^5+−x^5)+(25x^3+8x^3)+(−4+4)$

$=8x^5+33x^3$

In case you missed that, the answer is:

$=8x^5+33x^3$

Hope this helped! :)

( ﾟдﾟ)つ Bye