+0  
 
0
541
2
avatar

factor completely 256x^8-1

 Apr 25, 2016
 #1
avatar
0

Factor the following:
256 x^8-1

256 x^8-1 = (16 x^4)^2-1^2:
(16 x^4)^2-1^2

Factor the difference of two squares. (16 x^4)^2-1^2 = (16 x^4-1) (16 x^4+1):
(16 x^4-1) (16 x^4+1)

16 x^4-1 = (4 x^2)^2-1^2:
(4 x^2)^2-1^2 (16 x^4+1)

Factor the difference of two squares. (4 x^2)^2-1^2 = (4 x^2-1) (4 x^2+1):
(4 x^2-1) (4 x^2+1) (16 x^4+1)

4 x^2-1 = (2 x)^2-1^2:
(2 x)^2-1^2 (4 x^2+1) (16 x^4+1)

Factor the difference of two squares. (2 x)^2-1^2 = (2 x-1) (2 x+1):
Answer: |  (2 x-1) (2 x+1) (4 x^2+1) (16 x^4+1)

 Apr 25, 2016
 #2
avatar+130514 
0

256x^8  - 1  =

 

[2x]^8  - 1  =

 

( [2x]^4  - 1 ) ([2x]^4 + 1)  =

 

( [ 2x]^2 -1) ( [2x]^2 + 1) ( [2x]^4 + 1)  =

 

( 2x - 1) (2x + 1) ( [2x]^2 + 1) ( [2x]^4 + 1 )  =

 

(2x -1) (2x + 1) (4x^2 + 1) (16x^4 + 1)

 

 

cool cool cool

 Apr 25, 2016

0 Online Users