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Hi, how would one factorise this sum?

\(4x^2-4xy+y^2-9\)

 

please help....thank you..

 Jul 23, 2018

Best Answer 

 #1
avatar+21338 
+1

factorise

4x^2-4xy+y^2-9

\(4x^2-4xy+y^2-9\)

 

\(\begin{array}{|rcll|} \hline && 4x^2-4xy+y^2-9 \\ &=& (4x^2-4xy+y^2) -9 \\ &=& (2x-y)(2x-y) -9 \\ &=& (2x-y)^2 -9 \\ &=& (2x-y)^2 - 3^2 \\ &=& [(2x-y) - 3][(2x-y) + 3] \\ &=& (2x-y - 3)(2x-y + 3) \\ \hline \end{array}\)

 

laugh

 Jul 23, 2018
 #1
avatar+21338 
+1
Best Answer

factorise

4x^2-4xy+y^2-9

\(4x^2-4xy+y^2-9\)

 

\(\begin{array}{|rcll|} \hline && 4x^2-4xy+y^2-9 \\ &=& (4x^2-4xy+y^2) -9 \\ &=& (2x-y)(2x-y) -9 \\ &=& (2x-y)^2 -9 \\ &=& (2x-y)^2 - 3^2 \\ &=& [(2x-y) - 3][(2x-y) + 3] \\ &=& (2x-y - 3)(2x-y + 3) \\ \hline \end{array}\)

 

laugh

heureka Jul 23, 2018
 #2
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0

wow Heureka,

 

thanx a million!

Guest Jul 23, 2018

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