+0  
 
0
53
2
avatar

Hi, how would one factorise this sum?

\(4x^2-4xy+y^2-9\)

 

please help....thank you..

Guest Jul 23, 2018

Best Answer 

 #1
avatar+19813 
+1

factorise

4x^2-4xy+y^2-9

\(4x^2-4xy+y^2-9\)

 

\(\begin{array}{|rcll|} \hline && 4x^2-4xy+y^2-9 \\ &=& (4x^2-4xy+y^2) -9 \\ &=& (2x-y)(2x-y) -9 \\ &=& (2x-y)^2 -9 \\ &=& (2x-y)^2 - 3^2 \\ &=& [(2x-y) - 3][(2x-y) + 3] \\ &=& (2x-y - 3)(2x-y + 3) \\ \hline \end{array}\)

 

laugh

heureka  Jul 23, 2018
 #1
avatar+19813 
+1
Best Answer

factorise

4x^2-4xy+y^2-9

\(4x^2-4xy+y^2-9\)

 

\(\begin{array}{|rcll|} \hline && 4x^2-4xy+y^2-9 \\ &=& (4x^2-4xy+y^2) -9 \\ &=& (2x-y)(2x-y) -9 \\ &=& (2x-y)^2 -9 \\ &=& (2x-y)^2 - 3^2 \\ &=& [(2x-y) - 3][(2x-y) + 3] \\ &=& (2x-y - 3)(2x-y + 3) \\ \hline \end{array}\)

 

laugh

heureka  Jul 23, 2018
 #2
avatar
0

wow Heureka,

 

thanx a million!

Guest Jul 23, 2018

15 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.