Hi, how would one factorise this sum?
\(4x^2-4xy+y^2-9\)
please help....thank you..
+26367 factorise
4x^2-4xy+y^2-9
\(4x^2-4xy+y^2-9\)
\(\begin{array}{|rcll|} \hline && 4x^2-4xy+y^2-9 \\ &=& (4x^2-4xy+y^2) -9 \\ &=& (2x-y)(2x-y) -9 \\ &=& (2x-y)^2 -9 \\ &=& (2x-y)^2 - 3^2 \\ &=& [(2x-y) - 3][(2x-y) + 3] \\ &=& (2x-y - 3)(2x-y + 3) \\ \hline \end{array}\)
