factorization PLEASE HELP!!!

4(x-2)/(x-3) + 3/x = -3/x(x-3)

4x(x-2)/x(x-3) + 3(x-3)/x(x-3) = -3/x(x-3)

x cannot be 0 or 3

4x^2 - 8x + 3x - 9 = -3

4x^2 -5x -6 = 0

(x-2)(4x+3) = 0

x = 2 or x = - 3/4