Factorize 4x²+32x-132 please

4(x + 11) ( x - 3)   =  0   divide both sides by 4

(x + 11) (x - 3) = 0      set each factor to 0, and we get that x = -11 or  x = 3

Factorising this is very easy

4x²+32x-132 

just take 4 to be a common 

4(x^2+8x-33)

We can go  one step futher, Anonymous

4(x^2 + 8x - 33)  =

4(x + 11) ( x - 3)

And that's fully factored.....!!!!

Oh wow lol I thought about the other method which is like (?-?)(?-?)

Thanks

Oh and if all of that is 0, what is x?

I was just lazy to do the other steps C guy