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avatar+297 

Factorize (81b 4 - 18b 2 + 1).

 

a. (3b 2 + 1) (3b - 1) (3b + 1)                                                                                                                  

b. (3b - 1) (3b - 1) (3b - 1) (3b - 1)                                                                                                        

 c. (b - 1) (9b + 1) (b - 1) (9b + 1)                                                                                                            

d. (3b + 1) (3b + 1) (3b - 1) (3b - 1)

 Aug 11, 2015

Best Answer 

 #1
avatar+23048 
+10

$$\small{\text{Factorize $(81b^4 - 18b^2 + 1)$. }}\\\\$$

 

$$\small{\text{$
\begin{array}{rcl}
81b^4 - 18b^2 + 1 \\
&=& [9b^2-1]^2 \\
&=& [(3b-1)(3b+1) ]^2\\
&=& (3b-1)^2(3b+1)^2 \\
&=& (3b-1)(3b-1) (3b+1)(3b+1) \\
d. &=& (3b+1)(3b+1) (3b-1)(3b-1) \\
\end{array}
$}}$$

 

 Aug 11, 2015
 #1
avatar+23048 
+10
Best Answer

$$\small{\text{Factorize $(81b^4 - 18b^2 + 1)$. }}\\\\$$

 

$$\small{\text{$
\begin{array}{rcl}
81b^4 - 18b^2 + 1 \\
&=& [9b^2-1]^2 \\
&=& [(3b-1)(3b+1) ]^2\\
&=& (3b-1)^2(3b+1)^2 \\
&=& (3b-1)(3b-1) (3b+1)(3b+1) \\
d. &=& (3b+1)(3b+1) (3b-1)(3b-1) \\
\end{array}
$}}$$

 

heureka Aug 11, 2015

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