Factorize (x2 -0.7x+0.49) into two terms such that: (x- something) (x- something)
Factorize (x2 -0.7x+0.49) into two terms such that: (x- something) (x- something)
I can see straight off that there are no real solutions to this.
There are imaginary solutions but you might not know about imaginary numbers yet.
look at the discriminant
\(\triangle=b^2-4ac=0.49-4*0.49<0\)
Hence there is no real roots so this cannot be factorised without using imaginary number :)