Factorize (x^{2} -0.7x+0.49) into two terms such that: (x- something) (x- something)

Guest Apr 29, 2017

#1**+1 **

Factorize (x2 -0.7x+0.49) into two terms such that: (x- something) (x- something)

I can see straight off that there are no real solutions to this.

There are imaginary solutions but you might not know about imaginary numbers yet.

look at the discriminant

\(\triangle=b^2-4ac=0.49-4*0.49<0\)

Hence there is no real roots so this cannot be factorised without using imaginary number :)

Melody
Apr 29, 2017