factorize

2x^2  = 8x       subtract 8x from both sides

2x^2 - 8x  = 0    factor

2x ( x - 4)  = 0 

Setting each factor to 0, we have

2x   =   0  [divide both sides by 2]                   and                                  x - 4   =   0   [add 4 to both sides]

x = 0                                                                 and                                    x =    4

I'm sorry can yo change that to English 

Solve for x:
2 x^2 = 8 x

Subtract 8 x from both sides:
2 x^2-8 x = 0

Factor x and constant terms from the left hand side:
2 x (x-4) = 0

Divide both sides by 2:
x (x-4) = 0

Split into two equations:
x-4 = 0 or x = 0

Add 4 to both sides:
Answer: | x = 4         or x = 0