πππ+ππππβπππβπππ

not even that hard to factor:

\(4x^4+12x^3-9x^2-27x\\=x(4x^3+12x^2-9x-27)\\=x(4x^2(x+3)-9(x+3))\\=x(4x^2-9)(x+3)\\=\boxed{x(2x+3)(2x-3)(x+3)}\)

btw if you didn't do it by hand then how did you do it?

I think what you meant to paste is

4x^{3}+12x^{3}-9x^{2}-27x

I mean, I'm not doing it by hand because that would be a pain so you can just take this a leave.

(x-1)(2x+3)(x-2)(2x-3)

Yay!

magic.