πππ+ππππβπππβπππ
not even that hard to factor:
\(4x^4+12x^3-9x^2-27x\\=x(4x^3+12x^2-9x-27)\\=x(4x^2(x+3)-9(x+3))\\=x(4x^2-9)(x+3)\\=\boxed{x(2x+3)(2x-3)(x+3)}\)
btw if you didn't do it by hand then how did you do it?
I think what you meant to paste is
4x3+12x3-9x2-27x
I mean, I'm not doing it by hand because that would be a pain so you can just take this a leave.
(x-1)(2x+3)(x-2)(2x-3)
Yay!
magic.
