hmm. are you sure this is it? or can you give some context. Im not sure what the x is doing in this equation, and it doesn't cancel out.
The left hand side would be equal to \([C_0(1+r)](rx+1)\), so maybe \(rx+1=r+1\), so \(x=1\). Thats the only way i can think of
I think the 'X' is the multiplication symbol.....
(1+r) c + r(1+r)c = c ( 1+ r)^2 ?? Expand LEFT side
c + r c + r c + c r^2 = c ( 1+r)^2 Simplify LEFT side a bit
c + 2rc + cr^2 = c (1+r)^2 Factor out 'c' on the LEFT
c ( 1 + 2r + r^2 ) = c ( 1+r)^2 Reduce LEFT side
c (1+r)^2 = c (1+r)^2 <===== TRUE ! !