How many natural-number factors does N have if N=2^4*3^8*5^2*7^2?
you can simplyfy this into 4^2 * 81^2 * 5^2 * 7^2
so you can have 2, 4, 8, 16, 9, 6, 3, 81, 25, 5, 15, 49, 7, and 45 just to name a few. Try to find out more by multypliying some of the numbers.
(4 + 1)(8 + 1)(2 + 1)(2 + 1) = 5 * 9 * 3 * 3 = 45 * 9 = 405
