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What is the number of total factors for (a^3b^5)^4 if a and b are two different primes?

 Feb 22, 2021

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 #1
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\((a^3b^5)^4 = a^{12}b^{20}\)

 

The number of factors is (12+1)(20+1) = 273.

 Feb 22, 2021
 #1
avatar+944 
+1
Best Answer

\((a^3b^5)^4 = a^{12}b^{20}\)

 

The number of factors is (12+1)(20+1) = 273.

CubeyThePenguin Feb 22, 2021

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