+1678 What is the number of total factors for (a^3b^5)^4 if a and b are two different primes?
+1223 \((a^3b^5)^4 = a^{12}b^{20}\)
The number of factors is (12+1)(20+1) = 273.
+1223 \((a^3b^5)^4 = a^{12}b^{20}\)
The number of factors is (12+1)(20+1) = 273.
