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How many natural-number factors does N have if N=2^4*3^8*5^2*7^2?

 Aug 15, 2021
 #1
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The number of factors is 120.

 Aug 15, 2021
 #2
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2^4*3^8*5^2*7^2==128,595,600

 

It has: [4+1] x [8+1] x [2+1] x [2+1]==5  x  9  x  3  x  3 ==405 divisors

 Aug 15, 2021

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