How many natural-number factors does N have if N=2^4*3^8*5^2*7^2?
The number of factors is 120.
2^4*3^8*5^2*7^2==128,595,600
It has: [4+1] x [8+1] x [2+1] x [2+1]==5 x 9 x 3 x 3 ==405 divisors
